What is the foci (x-2)=3(y-5)^2 ?

The foci (x-2)=3(y-5)^2 is (25/12 ,5)

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foci (x-2)=3(y-5)^2

foci

(x - 2) = 3 (y - 5)^{2}

(\frac{25}{12}, 5)

Solution steps

Rewrite

(x - 2) = 3 (y - 5)^{2}

in the standard form:

4 \cdot \frac{1}{12} (x - 2) = (y - 5)^{2}

(h, k) = (2, 5), p = \frac{1}{12}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(2, 5)

along the x-axis

(2 + p, 5)

= (2 + \frac{1}{12}, 5)

Refine

(\frac{25}{12}, 5)

y = 6 x^{2} - 3 x 5

+ (y - 2) = 3 (x - 5)^{2}

- 0.5 x^{2} - 3

(y - 3)^{2} + 12 x = 0

y = 4 x^{2} - 4 x^{1}