Solution

vertices

Solution

Solution steps
Rewrite in the standard form:
Therefore parabola properties are:

Graph

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Popular Examples

vertices y=3x^2+2x+6vertices f(x)=4x^2-3vertices f(x)=-x^2+4x+12foci y^2=12xfoci y=(x^2x^1)/x

Frequently Asked Questions (FAQ)

  • What is the vertices (y+6)^2=12(x+1) ?

    The vertices (y+6)^2=12(x+1) is (h,k)=(-1,-6),p=3