Solution
vertices
Solution
Solution steps
Rewrite in the standard form
Therefore parabola properties are:
Graph
Popular Examples
vertices f(x)=(x+4)^2vertices f(x)=x^2+3x+1/4vertices f(x)=-x^2-2xvertices f(x)=x^2+6x+2vertices f(x)=x^2+6x+3
Frequently Asked Questions (FAQ)
What is the vertices 2y^2-8x-24y+56=0 ?
The vertices 2y^2-8x-24y+56=0 is (h,k)=(-2,6),p=1