What is the vertices f(x)=-x^2-2x ?

The vertices f(x)=-x^2-2x is Maximum (-1,1)

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vertices f(x)=-x^2-2x

vertices

Maximum (- 1, 1)

Solution steps

y = - x^{2} - 2 x

The parabola parameters are:

a = - 1, b = - 2, c = 0

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 2 )}{2 ( - 1 )}

Simplify

x_{v} = - 1

Plug in

x_{v} = - 1

to find the

y_{v}

value

y_{v} = 1

Therefore the parabola vertex is

(- 1, 1)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = - 1

Maximum (- 1, 1)