What is the vertices y=14(x-4)(x+10) ?

The vertices y=14(x-4)(x+10) is Minimum (-3,-686)

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vertices y=14(x-4)(x+10)

vertices

y = 14 (x - 4) (x + 10)

Minimum (- 3, - 686)

Solution steps

y = 14 (x - 4) (x + 10)

y = 14 (x - 4) (x + 10)

The parabola parameters are:

a = 14, m = 4, n = - 10

x_{v} = \frac{m + n}{2}

x_{v} = \frac{4 + ( - 10 )}{2}

Simplify

x_{v} = - 3

Plug in

x_{v} = - 3

to find the

y_{v}

value

y_{v} = - 686

Therefore the parabola vertex is

(- 3, - 686)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 14

Minimum (- 3, - 686)

x^{2} + 8 x - 80

f (x) = x^{2} - 6 x - 16

f (x) = 2 x + x^{2}

(x + 2)^{2} = - 6 (y - 1)

y = 2 x^{2} - x

What is the vertices y=14(x-4)(x+10) ?
The vertices y=14(x-4)(x+10) is Minimum (-3,-686)