What is the vertices y=x^2-13 ?

The vertices y=x^2-13 is Minimum (0,-13)

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vertices y=x^2-13

vertices

y = x^{2} - 13

Minimum (0, - 13)

Solution steps

y = x^{2} - 13

The parabola parameters are:

a = 1, b = 0, c = - 13

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 \cdot 1}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = - 13

Therefore the parabola vertex is

(0, - 13)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (0, - 13)

f (x) = 3 x^{2} - 2 x

y = - x^{2} + 80 x - 700

x^{2} + 2 x - 24

y = 2 x^{2} + 12 x + 14

x^{2} - 3 x - 4