What is the eccentricity (x^2}{25}+\frac{y^2)/9 =1 ?

The eccentricity (x^2}{25}+\frac{y^2)/9 =1 is 4/5

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eccentricity (x^2}{25}+\frac{y^2)/9 =1

eccentricity

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

\frac{4}{5}

Decimal

0.8

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 3

= \frac{5 ^{2} - 3 ^{2}}{5}

\frac{5 ^{2} - 3 ^{2}}{5} = \frac{4}{5}

= \frac{4}{5}

x = y^{2} - 4

\frac{( x - 5 ) ^{2}}{4} + \frac{( y + 3 ) ^{2}}{16} = 1

(x - 2)^{2} = 8 y

y = 2 - x - 2 x^{2}

\frac{x ^{2}}{36} + \frac{y ^{2}}{9} = 1

What is the eccentricity (x^2}{25}+\frac{y^2)/9 =1 ?
The eccentricity (x^2}{25}+\frac{y^2)/9 =1 is 4/5