What is the eccentricity (x^2}{25}+\frac{y^2)/9 =1 ?

The eccentricity (x^2}{25}+\frac{y^2)/9 =1 is 4/5

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eccentricity (x^2}{25}+\frac{y^2)/9 =1

eccentricity

\frac{4}{5}

Decimal

0.8

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 5, b = 3

= \frac{5 ^{2} - 3 ^{2}}{5}

\frac{5 ^{2} - 3 ^{2}}{5} = \frac{4}{5}

= \frac{4}{5}

What is the eccentricity (x^2}{25}+\frac{y^2)/9 =1 ?
The eccentricity (x^2}{25}+\frac{y^2)/9 =1 is 4/5