vertices y=x^2-6x+8

{ "query": { "display": "vertices $$y=x^{2}-6x+8$$", "symbolab_question": "CONIC#vertices y=x^{2}-6x+8" }, "solution": { "level": "PERFORMED", "subject": "Geometry", "topic": "Parabola", "subTopic": "vertices", "default": "\\mathrm{Minimum}\\:(3,-1)", "meta": { "showVerify": true } }, "methods": [ { "method": "Find vertex using polynomial form", "query": { "display": "vertex quadratic $$y=x^{2}-6x+8$$", "symbolab_question": "vertexquadratic y=x^{2}-6x+8" } }, { "method": "Find vertex using parabola form", "query": { "display": "vertex parabola $$y=x^{2}-6x+8$$", "symbolab_question": "vertexparabola y=x^{2}-6x+8" } }, { "method": "Find vertex using vertex form", "query": { "display": "vertex form $$y=x^{2}-6x+8$$", "symbolab_question": "vertexform y=x^{2}-6x+8" } }, { "method": "Find vertex using averaging the zeros", "query": { "display": "vertex zeros $$y=x^{2}-6x+8$$", "symbolab_question": "vertexzeros y=x^{2}-6x+8" } } ], "steps": { "type": "interim", "title": "Parabola vertex given $$y=x^{2}-6x+8:{\\quad}$$Minimum $$\\left(3,\\:-1\\right)$$", "input": "y=x^{2}-6x+8", "steps": [ { "type": "definition", "title": "Parabola equation in polynomial form", "text": "The vertex of an up-down facing parabola of the form $$y=ax^2+bx+c\\:$$is $$x_{v}=-\\frac{b}{2a}$$" }, { "type": "step", "primary": "The parabola parameters are:", "result": "a=1,\\:b=-6,\\:c=8" }, { "type": "step", "primary": "$$x_{v}=-\\frac{b}{2a}$$", "result": "x_{v}=-\\frac{\\left(-6\\right)}{2\\cdot\\:1}" }, { "type": "step", "primary": "Simplify", "result": "x_{v}=3" }, { "type": "interim", "title": "Plug in $$x_{v}=3\\:$$to find the $$y_{v}\\:$$value", "input": "y_{v}=3^{2}-6\\cdot\\:3+8", "result": "y_{v}=-1", "steps": [ { "type": "step", "primary": "Simplify", "result": "y_{v}=-1" } ], "meta": { "interimType": "Plug In Value 2Eq" } }, { "type": "step", "primary": "Therefore the parabola vertex is", "result": "\\left(3,\\:-1\\right)" }, { "type": "step", "primary": "If $$a<0,\\:$$then the vertex is a maximum value<br/>If $$a>0,\\:$$then the vertex is a minimum value<br/>$$a=1$$", "result": "\\mathrm{Minimum}\\:\\left(3,\\:-1\\right)" } ], "meta": { "solvingClass": "Parabola" } }, "plot_output": { "meta": { "plotInfo": { "variable": "x", "funcsToDraw": { "funcs": [ { "evalFormula": "y=\\frac{(x-3)^{2}}{4\\frac{1}{4}}-1", "displayFormula": "4\\frac{1}{4}(y-(-1))=(x-3)^{2}", "attributes": { "color": "PURPLE", "lineType": "NORMAL", "isAsymptote": false } }, { "evalFormula": "y=-\\frac{5}{4}", "displayFormula": "y=-\\frac{5}{4}", "attributes": { "color": "GRAY", "lineType": "NORMAL", "labels": [ "\\mathrm{directrix}" ], "isAsymptote": false } } ] }, "pointsToDraw": { "pointsLatex": [ "(3,-1)", "(3,-\\frac{3}{4})" ], "pointsDecimal": [ { "fst": 3, "snd": -1 }, { "fst": 3, "snd": -0.75 } ], "attributes": [ { "color": "PURPLE", "labels": [ "\\mathrm{vertex}" ], "labelTypes": [ "DEFAULT" ], "labelColors": [ "PURPLE" ] }, { "color": "PURPLE", "labels": [ "\\mathrm{focus}" ], "labelTypes": [ "DEFAULT" ], "labelColors": [ "PURPLE" ] } ] }, "functionChanges": [ { "origFormulaLatex": [], "finalFormulaLatex": [], "plotTitle": "4\\cdot \\frac{1}{4}(y-(-1))=(x-3)^{2}", "paramsLatex": [], "paramsReplacementsLatex": [] } ], "localBoundingBox": { "xMin": -1.1428571428571423, "xMax": 4.571428571428571, "yMin": -3.6999999999999997, "yMax": 2.014285714285714 } }, "showViewLarger": true } }, "meta": { "showVerify": true } }