What is the vertices 5x^2+20x-17 ?

The vertices 5x^2+20x-17 is Minimum (-2,-37)

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vertices 5x^2+20x-17

vertices

5 x^{2} + 20 x - 17

Minimum (- 2, - 37)

Solution steps

y = 5 x^{2} + 20 x - 17

The parabola parameters are:

a = 5, b = 20, c = - 17

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{20}{2 \cdot 5}

Simplify

x_{v} = - 2

Plug in

x_{v} = - 2

to find the

y_{v}

value

y_{v} = - 37

Therefore the parabola vertex is

(- 2, - 37)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 5

Minimum (- 2, - 37)

y = 2 x^{2} + 24 x - 6

- x^{2} + 4

y^{2} - 6 y = 8 x - 1

y = - 2 (x - 3)^{2} + 4

f (x) = x^{2} - 2 x + 2