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vertices y^2-6y=8x-1

Solution

vertices

y^{2} - 6 y = 8 x - 1

Solution

(h, k) = (- 1, 3), p = 2

Solution steps

y^{2} - 6 y = 8 x - 1

Rewrite

y^{2} - 6 y = 8 x - 1

in the standard form

4 \cdot 2 (x - (- 1)) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 3), p = 2

Popular Examples

vertices y=-2(x-3)^2+4 vertices

y = - 2 (x - 3)^{2} + 4

vertices f(x)=x^2-2x+2 vertices

f (x) = x^{2} - 2 x + 2

vertices f(x)=x^2+10x+16 vertices

f (x) = x^{2} + 10 x + 16

vertices f(x)=x^2-10x+25 vertices

f (x) = x^{2} - 10 x + 25

vertices f(x)=(x+2)^2-1 vertices

f (x) = (x + 2)^{2} - 1

Frequently Asked Questions (FAQ)

What is the vertices y^2-6y=8x-1 ?
The vertices y^2-6y=8x-1 is (h,k)=(-1,3),p=2