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Popular >

vertices y^2=4x

Solution

vertices

y^{2} = 4 x

Solution

(h, k) = (0, 0), p = 1

Solution steps

y^{2} = 4 x

Rewrite

y^{2} = 4 x

in the standard form:

4 \cdot 1 \cdot (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 1

Popular Examples

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y = x^{2} - 2 x - 3

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y = x^{2} + 2 x + 1

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10 + 3 x^{2}

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x^{2} - 5 x - 24

vertices y=(2x)^2 vertices

y = (2 x)^{2}

Frequently Asked Questions (FAQ)

What is the vertices y^2=4x ?
The vertices y^2=4x is (h,k)=(0,0),p=1