What is the vertices x^2-5x-24 ?

The vertices x^2-5x-24 is Minimum (5/2 ,-121/4)

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vertices x^2-5x-24

vertices

x^{2} - 5 x - 24

Minimum (\frac{5}{2}, - \frac{121}{4})

Solution steps

y = x^{2} - 5 x - 24

The parabola parameters are:

a = 1, b = - 5, c = - 24

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{( - 5 )}{2 \cdot 1}

Simplify

x_{v} = \frac{5}{2}

Plug in

x_{v} = \frac{5}{2}

to find the

y_{v}

value

y_{v} = - \frac{121}{4}

Therefore the parabola vertex is

(\frac{5}{2}, - \frac{121}{4})

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 1

Minimum (\frac{5}{2}, - \frac{121}{4})

y = (2 x)^{2}

y = 2 x^{2} - 19 x + 9

4 x^{2} - 20 x - 24 y + 97 = 0

y - 2 = (x - 1)^{2}

y = (x - 5)^{2}

What is the vertices x^2-5x-24 ?
The vertices x^2-5x-24 is Minimum (5/2 ,-121/4)