What is x=1-(y+2)^2 ?

The solution to x=1-(y+2)^2 is Parabola with (h,k)=(1,-2),p=-1/4

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x=1-(y+2)^2

x = 1 - (y + 2)^{2}

(h, k) = (1, - 2), p = - \frac{1}{4}

Solution steps

x = 1 - (y + 2)^{2}

Rewrite

x = 1 - (y + 2)^{2}

in the standard form:

4 (- \frac{1}{4}) (x - 1) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (1, - 2), p = - \frac{1}{4}

What is x=1-(y+2)^2 ?
The solution to x=1-(y+2)^2 is Parabola with (h,k)=(1,-2),p=-1/4