What is 2y=-4*(x+2)^2+m+5 ?

The solution to 2y=-4*(x+2)^2+m+5 is Parabola with (h,k)=(-2, m/2+5/2),p=-1/8

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2y=-4*(x+2)^2+m+5

2 y = - 4 \cdot (x + 2)^{2} + m + 5

(h, k) = (- 2, \frac{m}{2} + \frac{5}{2}), p = - \frac{1}{8}

Solution steps

2 y = - 4 (x + 2)^{2} + m + 5

Rewrite

2 y = - 4 (x + 2)^{2} + m + 5

in the standard form:

4 (- \frac{1}{8}) (y - \frac{m}{2} + \frac{5}{2}) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, \frac{m}{2} + \frac{5}{2}), p = - \frac{1}{8}

g (x) = - \frac{1}{2} x^{2} - 2

x, x = (t (x) + 2)^{2} + 5

2 x^{2} + 3 x + 5 y = 0

x = \frac{T ^{2} - 2 T}{8}

\frac{x ^{2}}{5} = - y

What is 2y=-4*(x+2)^2+m+5 ?
The solution to 2y=-4*(x+2)^2+m+5 is Parabola with (h,k)=(-2, m/2+5/2),p=-1/8