What is (x-7)^2=-14((y-3)/2) ?

The solution to (x-7)^2=-14((y-3)/2) is Parabola with (h,k)=(7,3),p=-7/4

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(x-7)^2=-14((y-3)/2)

(x - 7)^{2} = - 14 (\frac{y - 3}{2})

(h, k) = (7, 3), p = - \frac{7}{4}

Solution steps

(x - 7)^{2} = - 14 \cdot \frac{y - 3}{2}

Rewrite

(x - 7)^{2} = - 14 \cdot \frac{y - 3}{2}

in the standard form:

4 (- \frac{7}{4}) (y - 3) = (x - 7)^{2}

Therefore parabola properties are:

(h, k) = (7, 3), p = - \frac{7}{4}

8 x^{2} + 9 x + k (x) = 0

(x - 5)^{2} = 8 (6 - y)

4 (- 3) (y - (- 1)) = (x - 3)^{2}

- y = 4 (- x)^{2} + 2 (- x) - 4

(x - 2)^{2} = - 2 (y + 2)

What is (x-7)^2=-14((y-3)/2) ?
The solution to (x-7)^2=-14((y-3)/2) is Parabola with (h,k)=(7,3),p=-7/4