What is -y=4(-x)^2+2(-x)-4 ?

The solution to -y=4(-x)^2+2(-x)-4 is Parabola with (h,k)=(1/4 , 17/4),p=-1/16

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-y=4(-x)^2+2(-x)-4

- y = 4 (- x)^{2} + 2 (- x) - 4

(h, k) = (\frac{1}{4}, \frac{17}{4}), p = - \frac{1}{16}

Solution steps

- y = 4 (- x)^{2} + 2 (- x) - 4

Rewrite

- y = 4 (- x)^{2} + 2 (- x) - 4

in the standard form

4 (- \frac{1}{16}) (y - \frac{17}{4}) = (x - \frac{1}{4})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{4}, \frac{17}{4}), p = - \frac{1}{16}

(x - 2)^{2} = - 2 (y + 2)

x^{2} = \frac{1}{3} y

5 y = 7 x^{2} - 6

y = 6 x^{2} + 24 x

(y - 3)^{2} = - 8 (x - 3)

What is -y=4(-x)^2+2(-x)-4 ?
The solution to -y=4(-x)^2+2(-x)-4 is Parabola with (h,k)=(1/4 , 17/4),p=-1/16