What is 30(x^2-1)=11p(x) ?

The solution to 30(x^2-1)=11p(x) is Parabola with (h,k)=(0,-30/11),p= 11/120

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30(x^2-1)=11p(x)

30 (x^{2} - 1) = 11 p (x)

(h, k) = (0, - \frac{30}{11}), p = \frac{11}{120}

Solution steps

30 (x^{2} - 1) = 11 y

Rewrite

30 (x^{2} - 1) = 11 y

in the standard form

4 \cdot \frac{11}{120} (y - (- \frac{30}{11})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{30}{11}), p = \frac{11}{120}

y^{2} + 32 x = 0

x^{2} + 12 y + 60 = 0

y + x^{2} = - 3

\frac{( x + 5 )}{4} - \frac{y ^{2}}{4} = 1

(y - 3)^{2} = - 6 (x + 1)

What is 30(x^2-1)=11p(x) ?
The solution to 30(x^2-1)=11p(x) is Parabola with (h,k)=(0,-30/11),p= 11/120