What is ((x+5))/4-(y^2)/4 =1 ?

The solution to ((x+5))/4-(y^2)/4 =1 is Parabola with (h,k)=(-1,0),p= 1/4

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((x+5))/4-(y^2)/4 =1

\frac{( x + 5 )}{4} - \frac{y ^{2}}{4} = 1

(h, k) = (- 1, 0), p = \frac{1}{4}

Solution steps

\frac{x + 5}{4} - \frac{y ^{2}}{4} = 1

Rewrite

\frac{x + 5}{4} - \frac{y ^{2}}{4} = 1

in the standard form:

4 \cdot \frac{1}{4} (x - (- 1)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 1, 0), p = \frac{1}{4}

(y - 3)^{2} = - 6 (x + 1)

f (x) f (x) = x - 2

x^{2} + 6 x + 8 y - 7 = 0

x^{2} - 4 x - 24 y + 60 = 0

(x + 3)^{2} = (y + 4)

What is ((x+5))/4-(y^2)/4 =1 ?
The solution to ((x+5))/4-(y^2)/4 =1 is Parabola with (h,k)=(-1,0),p= 1/4