What is the answer to 8x-1+6x+3=S(x,y)y ?

The answer to 8x-1+6x+3=S(x,y)y is x=(yS-2)/(14)

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8x-1+6x+3=S(x,y)y

solve for

x, 8 x - 1 + 6 x + 3 = S y

x = \frac{y S - 2}{14}

Solution steps

8 x - 1 + 6 x + 3 = S y

Group like terms

8 x + 6 x - 1 + 3 = S y

Add similar elements:

8 x + 6 x = 14 x

14 x - 1 + 3 = S y

Add/Subtract the numbers:

- 1 + 3 = 2

14 x + 2 = S y

Move

2

to the right side

14 x = S y - 2

Divide both sides by

14

x = \frac{y S - 2}{14}

(x - 4)^{2} = 20 (y - 6)

(x - 3)^{2} = 5 (y - 2)

(x - 4)^{2} - 2 (y + 8) = 0

- x^{2} - 11 x - y - 28 \geq 0

x = \frac{( 5 y + 3 )}{7 x - 13}

What is the answer to 8x-1+6x+3=S(x,y)y ?
The answer to 8x-1+6x+3=S(x,y)y is x=(yS-2)/(14)