What is -x^2-11x-y-28>= 0 ?

The solution to -x^2-11x-y-28>= 0 is Parabola with (h,k)=(-11/2 , 9/4),p=-1/4

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-x^2-11x-y-28>= 0

- x^{2} - 11 x - y - 28 \geq 0

(h, k) = (- \frac{11}{2}, \frac{9}{4}), p = - \frac{1}{4}

Solution steps

- x^{2} - 11 x - y - 28 \geq 0

Rewrite

- x^{2} - 11 x - y - 28 \geq 0

in the standard form

4 (- \frac{1}{4}) (y - \frac{9}{4}) = (x - (- \frac{11}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{11}{2}, \frac{9}{4}), p = - \frac{1}{4}

x = \frac{( 5 y + 3 )}{7 x - 13}

(x - h)^{(2)} = 4 p (y - k)

x = 2 - y - y^{2}

(x - 3)^{2} = 16 (y - 1)

f (x) = 2 x^{2} + 3 x - 4.2 (f (x))

What is -x^2-11x-y-28>= 0 ?
The solution to -x^2-11x-y-28>= 0 is Parabola with (h,k)=(-11/2 , 9/4),p=-1/4