What is x^2+226x-660y+49=0 ?

The solution to x^2+226x-660y+49=0 is Parabola with (h,k)=(-113,-212/11),p=165

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x^2+226x-660y+49=0

x^{2} + 226 x - 660 y + 49 = 0

(h, k) = (- 113, - \frac{212}{11}), p = 165

Solution steps

x^{2} + 226 x - 660 y + 49 = 0

Rewrite

x^{2} + 226 x - 660 y + 49 = 0

in the standard form

4 \cdot 165 (y - (- \frac{212}{11})) = (x - (- 113))^{2}

Therefore parabola properties are:

(h, k) = (- 113, - \frac{212}{11}), p = 165

x = 3 (y - 3)^{2} - 6

(x + 1)^{2} = 5 (y - 2)

x = 3 (y - 3)^{2} - 5

- f (x) = - 3 (x)^{2} + (- 3) (x) - 3

yy - 72 = \frac{4}{31} (x - 110)

What is x^2+226x-660y+49=0 ?
The solution to x^2+226x-660y+49=0 is Parabola with (h,k)=(-113,-212/11),p=165