What is -f(x)=-3(x)^2+(-3)(x)-3 ?

The solution to -f(x)=-3(x)^2+(-3)(x)-3 is Parabola with (h,k)=(-1/2 , 9/4),p= 1/12

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-f(x)=-3(x)^2+(-3)(x)-3

- f (x) = - 3 (x)^{2} + (- 3) (x) - 3

(h, k) = (- \frac{1}{2}, \frac{9}{4}), p = \frac{1}{12}

Solution steps

- y = - 3 x^{2} + (- 3) x - 3

Rewrite

- y = - 3 x^{2} + (- 3) x - 3

in the standard form

4 \cdot \frac{1}{12} (y - \frac{9}{4}) = (x - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{2}, \frac{9}{4}), p = \frac{1}{12}

yy - 72 = \frac{4}{31} (x - 110)

y = - 0.9 (x - 1.3)^{2} + 2.3

(x - 15)^{2} = 12 (y - 3)

(x + 3)^{2} = - 20 (y + 2)

(x + 1)^{2} = 5 (y - 1)

What is -f(x)=-3(x)^2+(-3)(x)-3 ?
The solution to -f(x)=-3(x)^2+(-3)(x)-3 is Parabola with (h,k)=(-1/2 , 9/4),p= 1/12