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Popular >

4(y+1)^2=x

Solution

4 (y + 1)^{2} = x

Solution

(h, k) = (0, - 1), p = \frac{1}{16}

Solution steps

4 (y + 1)^{2} = x

Rewrite

4 (y + 1)^{2} = x

in the standard form:

4 \cdot \frac{1}{16} (x - 0) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (0, - 1), p = \frac{1}{16}

Popular Examples

1+(4(x+1))/(x^2+8s+16)=0

1 + \frac{4 ( x + 1 )}{x ^{2} + 8 s + 16} = 0

3 - 2 x = \frac{5 y}{x}

4(-5/4)(x-9/2)=(y-(-5/2))^2

4 (- \frac{5}{4}) (x - \frac{9}{2}) = (y - (- \frac{5}{2}))^{2}

- (y - 1) y = x

((x+5)^2)/(100)+((y-2^2))/(36)=1

\frac{( x + 5 ) ^{2}}{100} + \frac{( y - 2 ^{2} )}{36} = 1

Frequently Asked Questions (FAQ)

What is 4(y+1)^2=x ?
The solution to 4(y+1)^2=x is Parabola with (h,k)=(0,-1),p= 1/16