What is 4(-5/4)(x-9/2)=(y-(-5/2))^2 ?

The solution to 4(-5/4)(x-9/2)=(y-(-5/2))^2 is Parabola with (h,k)=(9/2 ,-5/2),p=-5/4

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4(-5/4)(x-9/2)=(y-(-5/2))^2

4 (- \frac{5}{4}) (x - \frac{9}{2}) = (y - (- \frac{5}{2}))^{2}

(h, k) = (\frac{9}{2}, - \frac{5}{2}), p = - \frac{5}{4}

Solution steps

4 (- \frac{5}{4}) (x - \frac{9}{2}) = (y - (- \frac{5}{2}))^{2}

Rewrite

4 (- \frac{5}{4}) (x - \frac{9}{2}) = (y - (- \frac{5}{2}))^{2}

in the standard form:

4 (- \frac{5}{4}) (x - \frac{9}{2}) = (y - (- \frac{5}{2}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{2}, - \frac{5}{2}), p = - \frac{5}{4}

- (y - 1) y = x

\frac{( x + 5 ) ^{2}}{100} + \frac{( y - 2 ^{2} )}{36} = 1

97 + a^{2} = b

f (x) = - 3 x^{2} + x + 9

5 x^{2} + 3 x + k (x) = 0

What is 4(-5/4)(x-9/2)=(y-(-5/2))^2 ?
The solution to 4(-5/4)(x-9/2)=(y-(-5/2))^2 is Parabola with (h,k)=(9/2 ,-5/2),p=-5/4