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Popular >

y=8(x+2)^2-1

Solution

y = 8 (x + 2)^{2} - 1

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq - 1

X Intercepts : (\frac{1}{2 2} - 2, 0), (- \frac{1}{2 2} - 2, 0), Y Intercepts : (0, 31)

Vertex : Minimum (- 2, - 1)

Inverse : \frac{2 x + 1}{4} - 2, - \frac{2 x + 1}{4} - 2

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [- 1, \infty)

Solution steps

Domain of

8 (x + 2)^{2} - 1 : - \infty < x < \infty

Range of

8 (x + 2)^{2} - 1 : f (x) \geq - 1

Axis interception points of

8 (x + 2)^{2} - 1 :

X Intercepts

: (\frac{1}{2 2} - 2, 0), (- \frac{1}{2 2} - 2, 0),

Y Intercepts

: (0, 31)

Vertex of

8 (x + 2)^{2} - 1 :

Minimum

(- 2, - 1)

Inverse of

8 (x + 2)^{2} - 1 : \frac{2 x + 1}{4} - 2, - \frac{2 x + 1}{4} - 2

Popular Examples

(y-7)^2=-12(x+1)

(y - 7)^{2} = - 12 (x + 1)

y + 6 = x^{(2)} - x

4 x^{2} + 3 x + k (x) = 0

f(x)=-x^2*1/2+3.75x-3

f (x) = - x^{2} \cdot \frac{1}{2} + 3.75 x - 3

4 (y + 1)^{2} = x

Frequently Asked Questions (FAQ)

What is the y=8(x+2)^2-1 ?
The y=8(x+2)^2-1 is