What is (9x-45)/3 =y^2-9y ?

The solution to (9x-45)/3 =y^2-9y is Parabola with (h,k)=(-27/4 , 9/2),p= 3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(9x-45)/3 =y^2-9y

\frac{9 x - 45}{3} = y^{2} - 9 y

(h, k) = (- \frac{27}{4}, \frac{9}{2}), p = \frac{3}{4}

Solution steps

\frac{9 x - 45}{3} = y^{2} - 9 y

Rewrite

\frac{9 x - 45}{3} = y^{2} - 9 y

in the standard form

4 \cdot \frac{3}{4} (x - (- \frac{27}{4})) = (y - \frac{9}{2})^{2}

Therefore parabola properties are:

(h, k) = (- \frac{27}{4}, \frac{9}{2}), p = \frac{3}{4}

- 9 x^{2} + 16 y + 36 x + 128 y + 76 = 0

x^{2} + 6 m (x) - 45 = 0

(3 + x) 6 x + 4 y = 50

y = - 0.3 (x - 1.7)^{2} + 19

2 y - 2 = 3 x^{2} + 4 x + 2

What is (9x-45)/3 =y^2-9y ?
The solution to (9x-45)/3 =y^2-9y is Parabola with (h,k)=(-27/4 , 9/2),p= 3/4