2y-2=3x^2+4x+2

Lösung

2 y - 2 = 3 x^{2} + 4 x + 2

(h, k) = (- \frac{2}{3}, \frac{4}{3}), p = \frac{1}{6}

Schritte zur Lösung

2 y - 2 = 3 x^{2} + 4 x + 2

Rewrite

2 y - 2 = 3 x^{2} + 4 x + 2

in the standard form

4 \cdot \frac{1}{6} (y - \frac{4}{3}) = (x - (- \frac{2}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{2}{3}, \frac{4}{3}), p = \frac{1}{6}

h (x) = (x + 1)^{2} + 3

(x + 2) x + (y - 2) = 0

y = 60 x - 2 x^{2}

x^{2} + 4 x - 2 y + 6 = 0

- y^{2} = - 4 x