5x^2-3y=4

Lösung

5 x^{2} - 3 y = 4

(h, k) = (0, - \frac{4}{3}), p = \frac{3}{20}

Schritte zur Lösung

5 x^{2} - 3 y = 4

Rewrite

5 x^{2} - 3 y = 4

in the standard form:

4 \cdot \frac{3}{20} (y - (- \frac{4}{3})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{4}{3}), p = \frac{3}{20}