x=y^2+4y-5

Lösung

x = y^{2} + 4 y - 5

(h, k) = (- 9, - 2), p = \frac{1}{4}

Schritte zur Lösung

x = y^{2} + 4 y - 5

Rewrite

x = y^{2} + 4 y - 5

in the standard form

4 \cdot \frac{1}{4} (x - (- 9)) = (y - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 9, - 2), p = \frac{1}{4}