What is 5000y+2500x^2=1600 ?

The solution to 5000y+2500x^2=1600 is Parabola with (h,k)=(0, 8/25),p=-1/2

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5000y+2500x^2=1600

5000 y + 2500 x^{2} = 1600

(h, k) = (0, \frac{8}{25}), p = - \frac{1}{2}

Solution steps

5000 y + 2500 x^{2} = 1600

Rewrite

5000 y + 2500 x^{2} = 1600

in the standard form:

4 (- \frac{1}{2}) (y - \frac{8}{25}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{8}{25}), p = - \frac{1}{2}

9^{2} + 9 y^{2} + 42 x - 54 + 9 = 0

y^{2} = - 2 x - 2

\frac{1}{x} + \frac{1}{25 - x} = \frac{1}{z}

3 x^{2} - y - 4 = 0

3 (x - 4) 2 + 3 y^{2} = 54

What is 5000y+2500x^2=1600 ?
The solution to 5000y+2500x^2=1600 is Parabola with (h,k)=(0, 8/25),p=-1/2