What is 9^2+9y^2+42x-54+9=0 ?

The solution to 9^2+9y^2+42x-54+9=0 is Parabola with (h,k)=(-6/7 ,0),p=-7/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9^2+9y^2+42x-54+9=0

9^{2} + 9 y^{2} + 42 x - 54 + 9 = 0

(h, k) = (- \frac{6}{7}, 0), p = - \frac{7}{6}

Solution steps

9^{2} + 9 y^{2} + 42 x - 54 + 9 = 0

Rewrite

9^{2} + 9 y^{2} + 42 x - 54 + 9 = 0

in the standard form:

4 (- \frac{7}{6}) (x - (- \frac{6}{7})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{6}{7}, 0), p = - \frac{7}{6}

y^{2} = - 2 x - 2

\frac{1}{x} + \frac{1}{25 - x} = \frac{1}{z}

3 x^{2} - y - 4 = 0

3 (x - 4) 2 + 3 y^{2} = 54

i f (x) = 3 x^{2}

What is 9^2+9y^2+42x-54+9=0 ?
The solution to 9^2+9y^2+42x-54+9=0 is Parabola with (h,k)=(-6/7 ,0),p=-7/6