What is (7y)/(x+1)=3 7/(y+1) ?

The solution to (7y)/(x+1)=3 7/(y+1) is Parabola with (h,k)=(-13/12 ,-1/2),p= 3/4

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(7y)/(x+1)=3 7/(y+1)

\frac{7 y}{x + 1} = 3 \frac{7}{y + 1}

(h, k) = (- \frac{13}{12}, - \frac{1}{2}), p = \frac{3}{4}

Solution steps

\frac{7 y}{x + 1} = 3 \cdot \frac{7}{y + 1}

Rewrite

\frac{7 y}{x + 1} - 3 \cdot \frac{7}{y + 1} = 0

in the standard form

4 \cdot \frac{3}{4} (x - (- \frac{13}{12})) = (y - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{13}{12}, - \frac{1}{2}), p = \frac{3}{4}

y^{2} = 6 - 2 x

8 (x - 5) = (y - 2)^{2}

3^{2} + 3 y^{2} - 6 x + 9 y - 14 = 0

2 f (x) = - 3 x^{2} + x - 1

x^{2} + 10 x - y = 0

What is (7y)/(x+1)=3 7/(y+1) ?
The solution to (7y)/(x+1)=3 7/(y+1) is Parabola with (h,k)=(-13/12 ,-1/2),p= 3/4