What is 3^2+3y^2-6x+9y-14=0 ?

The solution to 3^2+3y^2-6x+9y-14=0 is Parabola with (h,k)=(-47/24 ,-3/2),p= 1/2

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3^2+3y^2-6x+9y-14=0

3^{2} + 3 y^{2} - 6 x + 9 y - 14 = 0

(h, k) = (- \frac{47}{24}, - \frac{3}{2}), p = \frac{1}{2}

Solution steps

3^{2} + 3 y^{2} - 6 x + 9 y - 14 = 0

Rewrite

3^{2} + 3 y^{2} - 6 x + 9 y - 14 = 0

in the standard form

4 \cdot \frac{1}{2} (x - (- \frac{47}{24})) = (y - (- \frac{3}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{47}{24}, - \frac{3}{2}), p = \frac{1}{2}

2 f (x) = - 3 x^{2} + x - 1

x^{2} + 10 x - y = 0

x = a t^{2}

6 = a b^{- 2}

- 4 x^{2} + 8 y + 64 = 0

What is 3^2+3y^2-6x+9y-14=0 ?
The solution to 3^2+3y^2-6x+9y-14=0 is Parabola with (h,k)=(-47/24 ,-3/2),p= 1/2