What is ((1-x))/((y-2))=((x+2))/((x-y)) ?

The solution to ((1-x))/((y-2))=((x+2))/((x-y)) is Parabola with (h,k)=(3/2 , 25/12),p=-3/4

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((1-x))/((y-2))=((x+2))/((x-y))

\frac{( 1 - x )}{( y - 2 )} = \frac{( x + 2 )}{( x - y )}

(h, k) = (\frac{3}{2}, \frac{25}{12}), p = - \frac{3}{4}

Solution steps

\frac{1 - x}{y - 2} = \frac{x + 2}{x - y}

Rewrite

\frac{1 - x}{y - 2} - \frac{x + 2}{x - y} = 0

in the standard form

4 (- \frac{3}{4}) (y - \frac{25}{12}) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, \frac{25}{12}), p = - \frac{3}{4}

3 y^{2} + 30 y - x + 71 = 0

(3 y - 6)^{2} = 36 (x - 2)

(y - 3) = - \frac{1}{4} (x + 4)^{2}

(x - 3)^{2} = 20 (y + 2)

x, 5 x - 6 - \frac{1}{2} k (x)^{2} + 2 k (x)^{2} = 0

What is ((1-x))/((y-2))=((x+2))/((x-y)) ?
The solution to ((1-x))/((y-2))=((x+2))/((x-y)) is Parabola with (h,k)=(3/2 , 25/12),p=-3/4