What is 3y^2+30y-x+71=0 ?

The solution to 3y^2+30y-x+71=0 is Parabola with (h,k)=(-4,-5),p= 1/12

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3y^2+30y-x+71=0

3 y^{2} + 30 y - x + 71 = 0

(h, k) = (- 4, - 5), p = \frac{1}{12}

Solution steps

3 y^{2} + 30 y - x + 71 = 0

Rewrite

3 y^{2} + 30 y - x + 71 = 0

in the standard form

4 \cdot \frac{1}{12} (x - (- 4)) = (y - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 5), p = \frac{1}{12}

(3 y - 6)^{2} = 36 (x - 2)

(y - 3) = - \frac{1}{4} (x + 4)^{2}

(x - 3)^{2} = 20 (y + 2)

x, 5 x - 6 - \frac{1}{2} k (x)^{2} + 2 k (x)^{2} = 0

a 9 a + 6 c = 8 a + 10 c

What is 3y^2+30y-x+71=0 ?
The solution to 3y^2+30y-x+71=0 is Parabola with (h,k)=(-4,-5),p= 1/12