vertices (x^2)/(25)+(y^2)/(25)=1

الحلّ

vertices

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

(0, 5), (0, - 5)

خطوات الحلّ

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 5

(0, 0 + 5), (0, 0 - 5)

بسّط

(0, 5), (0, - 5)

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 3 ) ^{2}}{9} = 1

f (x) = x^{2} - 2 x + 4

x^{2} - 24 x - 12

16 x^{2} + 9 y^{2} = 144