What is the vertices (x^2)/(25)+(y^2)/(25)=1 ?

The vertices (x^2)/(25)+(y^2)/(25)=1 is (0,5),(0,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

vertices (x^2)/(25)+(y^2)/(25)=1

vertices

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

\frac{x ^{2}}{25} + \frac{y ^{2}}{25} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 5, a = 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 3 ) ^{2}}{9} = 1

f (x) = x^{2} - 2 x + 4

x^{2} - 24 x - 12

16 x^{2} + 9 y^{2} = 144

What is the vertices (x^2)/(25)+(y^2)/(25)=1 ?
The vertices (x^2)/(25)+(y^2)/(25)=1 is (0,5),(0,-5)