What is the asymptotes of (y^2)/(64)-(x^2)/(36)=1 ?

The asymptotes of (y^2)/(64)-(x^2)/(36)=1 is y=(4x)/3 ,\quad y=-(4x)/3

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asymptotes of (y^2)/(64)-(x^2)/(36)=1

asymptotes

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1

y = \frac{4 x}{3}, y = - \frac{4 x}{3}

Solution steps

y = \pm \frac{a}{b} (x - h) + k

Calculate Hyperbola properties

\frac{y ^{2}}{64} - \frac{x ^{2}}{36} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 8, b = 6

y = \frac{8}{6} (x - 0) + 0, y = - \frac{8}{6} (x - 0) + 0

Refine

y = \frac{4 x}{3}, y = - \frac{4 x}{3}

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 3 ) ^{2}}{9} = 1

f (x) = x^{2} - 2 x + 4

x^{2} - 24 x - 12

16 x^{2} + 9 y^{2} = 144

- x^{2} + y^{2} = 1

What is the asymptotes of (y^2)/(64)-(x^2)/(36)=1 ?
The asymptotes of (y^2)/(64)-(x^2)/(36)=1 is y=(4x)/3 ,\quad y=-(4x)/3