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Popular >

y^2+x-y=0

Solution

y^{2} + x - y = 0

Solution

(h, k) = (\frac{1}{4}, \frac{1}{2}), p = - \frac{1}{4}

Solution steps

y^{2} + x - y = 0

Rewrite

y^{2} + x - y = 0

in the standard form

4 (- \frac{1}{4}) (x - \frac{1}{4}) = (y - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{4}, \frac{1}{2}), p = - \frac{1}{4}

Popular Examples

- 4 z^{2} + 2 y - 7 = 0

(y-5)^2=-12(x-3)

(y - 5)^{2} = - 12 (x - 3)

solvefor f,f(x)^{-1}(x)=(1/(x-2))solve for

f, f (x)^{- 1} (x) = (\frac{1}{x - 2})

y^2-16x-2y+49=0

y^{2} - 16 x - 2 y + 49 = 0

4f(x)=7x^2-12x+15

4 f (x) = 7 x^{2} - 12 x + 15

Frequently Asked Questions (FAQ)

What is y^2+x-y=0 ?
The solution to y^2+x-y=0 is Parabola with (h,k)=(1/4 , 1/2),p=-1/4