What is 4f(x)=7x^2-12x+15 ?

The solution to 4f(x)=7x^2-12x+15 is Parabola with (h,k)=(6/7 , 69/28),p= 1/7

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4f(x)=7x^2-12x+15

4 f (x) = 7 x^{2} - 12 x + 15

(h, k) = (\frac{6}{7}, \frac{69}{28}), p = \frac{1}{7}

Solution steps

4 y = 7 x^{2} - 12 x + 15

Rewrite

4 y = 7 x^{2} - 12 x + 15

in the standard form

4 \cdot \frac{1}{7} (y - \frac{69}{28}) = (x - \frac{6}{7})^{2}

Therefore parabola properties are:

(h, k) = (\frac{6}{7}, \frac{69}{28}), p = \frac{1}{7}

(y + 3)^{2} = 16 x

y^{2} - 4 x + 7 = 0

x^{2} + y = 19

y \leq - x^{2} + 8 x

Y^{2} - X + 8 Y + 13 = 0

What is 4f(x)=7x^2-12x+15 ?
The solution to 4f(x)=7x^2-12x+15 is Parabola with (h,k)=(6/7 , 69/28),p= 1/7