(y-3)^2=10(x-2)

Lösung

(y - 3)^{2} = 10 (x - 2)

(h, k) = (2, 3), p = \frac{5}{2}

Schritte zur Lösung

(y - 3)^{2} = 10 (x - 2)

Rewrite

(y - 3)^{2} = 10 (x - 2)

in the standard form:

4 \cdot \frac{5}{2} (x - 2) = (y - 3)^{2}

Therefore parabola properties are:

(h, k) = (2, 3), p = \frac{5}{2}

x^{2} - 4 + 2 y = 0

\frac{y}{x} = \frac{x}{5}

- 3 x^{2} + 12 x - y - 13 = 0

(y - 1)^{2} = 2 (x - 1)

y - 5 = - \frac{5}{4} x^{2}