What is -3x^2+12x-y-13=0 ?

The solution to -3x^2+12x-y-13=0 is Parabola with (h,k)=(2,-1),p=-1/12

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-3x^2+12x-y-13=0

- 3 x^{2} + 12 x - y - 13 = 0

(h, k) = (2, - 1), p = - \frac{1}{12}

Solution steps

- 3 x^{2} + 12 x - y - 13 = 0

Rewrite

- 3 x^{2} + 12 x - y - 13 = 0

in the standard form

4 (- \frac{1}{12}) (y - (- 1)) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, - 1), p = - \frac{1}{12}

What is -3x^2+12x-y-13=0 ?
The solution to -3x^2+12x-y-13=0 is Parabola with (h,k)=(2,-1),p=-1/12