What is the foci x^2+(y^2)/(64)=1 ?

The foci x^2+(y^2)/(64)=1 is (0,3sqrt(7)),(0,-3sqrt(7))

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foci x^2+(y^2)/(64)=1

foci

x^{2} + \frac{y ^{2}}{64} = 1

(0, 37), (0, - 37)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

x^{2} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 8, a = 1

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 8^{2} - 1^{2} : 37

(0, 0 + 37), (0, 0 - 37)

Refine

(0, 37), (0, - 37)

What is the foci x^2+(y^2)/(64)=1 ?
The foci x^2+(y^2)/(64)=1 is (0,3sqrt(7)),(0,-3sqrt(7))