What is (x^2)/9+(y^2)/9 =1 ?

The solution to (x^2)/9+(y^2)/9 =1 is Circle with (a,b)=(0,0),r=3

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(x^2)/9+(y^2)/9 =1

\frac{x ^{2}}{9} + \frac{y ^{2}}{9} = 1

(a, b) = (0, 0), r = 3

Solution steps

\frac{x ^{2}}{9} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{9} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 3

x = y^{2} - 1

\frac{( x - 3 ) ^{2}}{81} - \frac{( y + 5 ) ^{2}}{144} = 1

x = \frac{1}{4} y^{2}

x^{2} + y^{2} - 4 y = 0

x^{2} = - 8 y

What is (x^2)/9+(y^2)/9 =1 ?
The solution to (x^2)/9+(y^2)/9 =1 is Circle with (a,b)=(0,0),r=3