What is ((x-2)^2)/2+((y-3^2))/2 =1 ?

The solution to ((x-2)^2)/2+((y-3^2))/2 =1 is Parabola with (h,k)=(2,11),p=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-2)^2)/2+((y-3^2))/2 =1

\frac{( x - 2 ) ^{2}}{2} + \frac{( y - 3 ^{2} )}{2} = 1

(h, k) = (2, 11), p = - \frac{1}{4}

Solution steps

\frac{( x - 2 ) ^{2}}{2} + \frac{y - 3 ^{2}}{2} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{2} + \frac{y - 3 ^{2}}{2} = 1

in the standard form:

4 (- \frac{1}{4}) (y - 11) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 11), p = - \frac{1}{4}

x^{2} + 2 y = 12

x^{2} - k (x) + 1681 = 0

16 x^{2} - 73 z + 36 = 0

y \geq - 2 x^{2} + 16 x - 29

2 x^{2} + 4 y + 5 = 0

What is ((x-2)^2)/2+((y-3^2))/2 =1 ?
The solution to ((x-2)^2)/2+((y-3^2))/2 =1 is Parabola with (h,k)=(2,11),p=-1/4