y>=-2x^2+16x-29

Lösung

y \geq - 2 x^{2} + 16 x - 29

(h, k) = (4, 3), p = - \frac{1}{8}

Schritte zur Lösung

y \geq - 2 x^{2} + 16 x - 29

Rewrite

y \geq - 2 x^{2} + 16 x - 29

in the standard form

4 (- \frac{1}{8}) (y - 3) = (x - 4)^{2}

Therefore parabola properties are:

(h, k) = (4, 3), p = - \frac{1}{8}

2 x^{2} + 4 y + 5 = 0

y^{2} = \frac{3}{16} x

(x - 2)^{2} = 12 y

D (h 3 + n) = tt

y^{1} = 3 x^{2} + 5 x - 2