What is x^2= 125/16 (y-20) ?

The solution to x^2= 125/16 (y-20) is Parabola with (h,k)=(0,20),p= 125/64

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x^2= 125/16 (y-20)

x^{2} = \frac{125}{16} (y - 20)

(h, k) = (0, 20), p = \frac{125}{64}

Solution steps

x^{2} = \frac{125}{16} (y - 20)

Rewrite

x^{2} = \frac{125}{16} (y - 20)

in the standard form:

4 \cdot \frac{125}{64} (y - 20) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 20), p = \frac{125}{64}

6 x + 6 y^{2} = 36

\frac{( x - 2 ) ^{2}}{2} + \frac{( y - 3 ^{2} )}{2} = 1

x^{2} + 2 y = 12

x^{2} - k (x) + 1681 = 0

16 x^{2} - 73 z + 36 = 0

What is x^2= 125/16 (y-20) ?
The solution to x^2= 125/16 (y-20) is Parabola with (h,k)=(0,20),p= 125/64