What is (y-2^2)/4-(x^2)/9 =1 ?

The solution to (y-2^2)/4-(x^2)/9 =1 is Parabola with (h,k)=(0,8),p= 9/16

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(y-2^2)/4-(x^2)/9 =1

\frac{y - 2 ^{2}}{4} - \frac{x ^{2}}{9} = 1

(h, k) = (0, 8), p = \frac{9}{16}

Solution steps

\frac{y - 2 ^{2}}{4} - \frac{x ^{2}}{9} = 1

Rewrite

\frac{y - 2 ^{2}}{4} - \frac{x ^{2}}{9} = 1

in the standard form:

4 \cdot \frac{9}{16} (y - 8) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 8), p = \frac{9}{16}

3 y^{(2)} = 10 x

x = y^{2} - y - 1

(Y + 4)^{2} = X + 3

yy - 2 = (2 - 1) (x - 1)

8 x^{2} + y = 13

What is (y-2^2)/4-(x^2)/9 =1 ?
The solution to (y-2^2)/4-(x^2)/9 =1 is Parabola with (h,k)=(0,8),p= 9/16