What is yy-sqrt(2)=(sqrt(2)-1)(x-1) ?

The solution to yy-sqrt(2)=(sqrt(2)-1)(x-1) is Parabola with (h,k)=(-sqrt(2)-1,0),p=(sqrt(2)-1)/4

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yy-sqrt(2)=(sqrt(2)-1)(x-1)

yy - 2 = (2 - 1) (x - 1)

(h, k) = (- 2 - 1, 0), p = \frac{2 - 1}{4}

Solution steps

yy - 2 = (2 - 1) (x - 1)

Rewrite

yy - 2 = (2 - 1) (x - 1)

in the standard form:

4 \cdot \frac{2 - 1}{4} (x - (- 2 - 1)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 2 - 1, 0), p = \frac{2 - 1}{4}

8 x^{2} + y = 13

4 x^{2} + 2 x = y - 2 - x^{2}

4 x^{2} + 6 x^{2} + 4 x - 2 y = 0

17 x^{2} + 16 y = 272

6 x^{2} + 7 x + k (x) = 0

What is yy-sqrt(2)=(sqrt(2)-1)(x-1) ?
The solution to yy-sqrt(2)=(sqrt(2)-1)(x-1) is Parabola with (h,k)=(-sqrt(2)-1,0),p=(sqrt(2)-1)/4