What is -(x-35)^2=4(4.5455)(y-13) ?

The solution to -(x-35)^2=4(4.5455)(y-13) is Parabola with (h,k)=(35,13),p=-4.5455

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-(x-35)^2=4(4.5455)(y-13)

- (x - 35)^{2} = 4 (4.5455) (y - 13)

(h, k) = (35, 13), p = - 4.5455

Solution steps

- (x - 35)^{2} = 4 \cdot 4.5455 (y - 13)

Rewrite

- (x - 35)^{2} = 4 \cdot 4.5455 (y - 13)

in the standard form:

4 (- 4.5455) (y - 13) = (x - 35)^{2}

Therefore parabola properties are:

(h, k) = (35, 13), p = - 4.5455

5.2 s + 0.1 r 0.7 (r + 0.2) + 3.2 = - 3 s

3 y = - x^{2} + 4

4 (- \frac{1}{8}) (x - \frac{57}{8}) = (y - \frac{5}{4})^{2}

2 x^{2} - 20 x + 2 m (x) > 0

x^{2} + 2 x - y = 2

What is -(x-35)^2=4(4.5455)(y-13) ?
The solution to -(x-35)^2=4(4.5455)(y-13) is Parabola with (h,k)=(35,13),p=-4.5455