What is 5.2s+0.1r0.7(r+0.2)+3.2=-3s ?

The solution to 5.2s+0.1r0.7(r+0.2)+3.2=-3s is Parabola with (h,k)=(-0.39015…,-0.1),p=-29.28571…

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5.2s+0.1r0.7(r+0.2)+3.2=-3s

5.2 s + 0.1 r 0.7 (r + 0.2) + 3.2 = - 3 s

(h, k) = (- 0.39015 \dots, - 0.1), p = - 29.28571 \dots

Solution steps

5.2 s + 0.1 r \cdot 0.7 (r + 0.2) + 3.2 = - 3 s

Rewrite

5.2 s + 0.1 r \cdot 0.7 (r + 0.2) + 3.2 = - 3 s

in the standard form

4 (- 29.28571 \dots) (s - (- 0.39015 \dots)) = (r - (- 0.1))^{2}

Therefore parabola properties are:

(h, k) = (- 0.39015 \dots, - 0.1), p = - 29.28571 \dots

3 y = - x^{2} + 4

4 (- \frac{1}{8}) (x - \frac{57}{8}) = (y - \frac{5}{4})^{2}

2 x^{2} - 20 x + 2 m (x) > 0

x^{2} + 2 x - y = 2

4 x^{2} + 4 y = 25

What is 5.2s+0.1r0.7(r+0.2)+3.2=-3s ?
The solution to 5.2s+0.1r0.7(r+0.2)+3.2=-3s is Parabola with (h,k)=(-0.39015…,-0.1),p=-29.28571…